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Ti–Al–Mo alloy possesses excellent mechanical propertiesMechanical properties, biocompatibilityBiocompatibility, physical propertiesProperties, etc. It is widely used in aerospace and marine engineering fields. In this paper, TiO2, Al2O3 and MoO3 were selected as raw materials, and Ti–Al–Mo alloy was prepared in NaCl–CaCl2 molten saltMolten salt system by molten saltMolten salt electro-deoxidation processProcess. The thermodynamicThermodynamic calculation was carried out for its reductionReduction processProcess to determine the reaction processProcess. The results show that at 873–1273 K, the O2− removed by cathodic reductionReduction will react with Ca2+ in the molten saltMolten salt to affect the raw materials, respectively, generating CaMoO4, CaTiO3, and CaAl12O19. Among them, the Mo component is preferentially reduced (MoO3/CaMoO4 → MoO2 → Mo), followed by the stepwise reductionReduction of the Ti component (TiO2/CaTiO3 → Ti3O5 → Ti2O3 → TiO → Ti), and finally the reductionReduction of the Al component (Al2O3/CaAl12O19 → Al), ultimately forming Ti–Al–Mo alloy.

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Thermodynamic Analysis on Preparation of Ti–Al–Mo Alloy by Molten Salt Electro-deoxidation Process

  • 会议论文

  • 发表日期：

    2026年

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  • Zekang Ban,
  • Hui Li,
  • Chang Liu

摘要

Ti–Al–Mo alloy possesses excellent mechanical propertiesMechanical properties, biocompatibilityBiocompatibility, physical propertiesProperties, etc. It is widely used in aerospace and marine engineering fields. In this paper, TiO2, Al2O3 and MoO3 were selected as raw materials, and Ti–Al–Mo alloy was prepared in NaCl–CaCl2 molten saltMolten salt system by molten saltMolten salt electro-deoxidation processProcess. The thermodynamicThermodynamic calculation was carried out for its reductionReduction processProcess to determine the reaction processProcess. The results show that at 873–1273 K, the O2− removed by cathodic reductionReduction will react with Ca2+ in the molten saltMolten salt to affect the raw materials, respectively, generating CaMoO4, CaTiO3, and CaAl12O19. Among them, the Mo component is preferentially reduced (MoO3/CaMoO4 → MoO2 → Mo), followed by the stepwise reductionReduction of the Ti component (TiO2/CaTiO3 → Ti3O5 → Ti2O3 → TiO → Ti), and finally the reductionReduction of the Al component (Al2O3/CaAl12O19 → Al), ultimately forming Ti–Al–Mo alloy.