<p>For <InlineEquation ID="IEq1"> <EquationSource Format="MATHML"><math> <mn>1</mn> <mo>≤</mo> <mi>p</mi> <mo>,</mo> <mi>q</mi> <mo>≤</mo> <mi mathvariant="normal">∞</mi> </math></EquationSource> <EquationSource Format="TEX">$1\le p,q\le \infty $</EquationSource> </InlineEquation>, the Nikolskii factor for a trigonometric polynomial <InlineEquation ID="IEq2"> <EquationSource Format="MATHML"><math> <msub> <mi>T</mi> <mi mathvariant="bold">a</mi> </msub> </math></EquationSource> <EquationSource Format="TEX">$T_{{\mathbf{a}}}$</EquationSource> </InlineEquation> is defined by <Equation ID="Equa"> <EquationSource Format="MATHML"><math> <msub> <mi>N</mi> <mrow> <mi>p</mi> <mo>,</mo> <mi>q</mi> </mrow> </msub> <mo stretchy="false">(</mo> <msub> <mi>T</mi> <mi mathvariant="bold">a</mi> </msub> <mo stretchy="false">)</mo> <mo>=</mo> <mfrac> <msub> <mrow> <mo stretchy="false">∥</mo> <msub> <mi>T</mi> <mi mathvariant="bold">a</mi> </msub> <mo stretchy="false">∥</mo> </mrow> <mi>q</mi> </msub> <msub> <mrow> <mo stretchy="false">∥</mo> <msub> <mi>T</mi> <mi mathvariant="bold">a</mi> </msub> <mo stretchy="false">∥</mo> </mrow> <mi>p</mi> </msub> </mfrac> <mo>,</mo> <mspace width="0.25em" /> <mspace width="0.25em" /> <msub> <mi>T</mi> <mi mathvariant="bold">a</mi> </msub> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> <mo>=</mo> <msub> <mi>a</mi> <mn>1</mn> </msub> <mo>+</mo> <munderover> <mo movablelimits="false">∑</mo> <mrow> <mi>k</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>n</mi> </munderover> <mo stretchy="false">(</mo> <msub> <mi>a</mi> <mrow> <mn>2</mn> <mi>k</mi> </mrow> </msub> <msqrt> <mn>2</mn> </msqrt> <mo>cos</mo> <mi>k</mi> <mi>x</mi> <mo>+</mo> <msub> <mi>a</mi> <mrow> <mn>2</mn> <mi>k</mi> <mo>+</mo> <mn>1</mn> </mrow> </msub> <msqrt> <mn>2</mn> </msqrt> <mo>sin</mo> <mi>k</mi> <mi>x</mi> <mo stretchy="false">)</mo> <mo>.</mo> </math></EquationSource> <EquationSource Format="TEX">\( N_{p,q}(T_{{\mathbf{a}}})= \frac{\|T_{{\mathbf{a}}}\|_{q}}{\|T_{{\mathbf{a}}}\|_{p}},\ \ T_{{ \mathbf{a}}}(x)=a_{1}+\sum \limits ^{n}_{k=1}(a_{2k}\sqrt{2}\cos kx+a_{2k+1} \sqrt{2}\sin kx). \)</EquationSource> </Equation> We study this average Nikolskii factor for random trigonometric polynomials with independent <InlineEquation ID="IEq3"> <EquationSource Format="MATHML"><math> <mi>N</mi> <mo stretchy="false">(</mo> <mn>0</mn> <mo>,</mo> <msup> <mi>σ</mi> <mn>2</mn> </msup> <mo stretchy="false">)</mo> </math></EquationSource> <EquationSource Format="TEX">$N(0,\sigma ^{2})$</EquationSource> </InlineEquation> coefficients and obtain the exact orders. For <InlineEquation ID="IEq4"> <EquationSource Format="MATHML"><math> <mn>1</mn> <mo>≤</mo> <mi>p</mi> <mo>&lt;</mo> <mi>q</mi> <mo>&lt;</mo> <mi mathvariant="normal">∞</mi> </math></EquationSource> <EquationSource Format="TEX">$1\leq p&lt; q&lt;\infty $</EquationSource> </InlineEquation>, the average Nikolskii factor is of order <InlineEquation ID="IEq5"> <EquationSource Format="MATHML"><math> <msup> <mi>n</mi> <mn>0</mn> </msup> </math></EquationSource> <EquationSource Format="TEX">$n^{0}$</EquationSource> </InlineEquation> (i.e., constant), as compared to the worst case bound of order <InlineEquation ID="IEq6"> <EquationSource Format="MATHML"><math> <msup> <mi>n</mi> <mrow> <mn>1</mn> <mo stretchy="false">/</mo> <mi>p</mi> <mo>−</mo> <mn>1</mn> <mo stretchy="false">/</mo> <mi>q</mi> </mrow> </msup> </math></EquationSource> <EquationSource Format="TEX">$n^{1/p-1/q}$</EquationSource> </InlineEquation>, and for <InlineEquation ID="IEq7"> <EquationSource Format="MATHML"><math> <mn>1</mn> <mo>≤</mo> <mi>p</mi> <mo>&lt;</mo> <mi>q</mi> <mo>=</mo> <mi mathvariant="normal">∞</mi> </math></EquationSource> <EquationSource Format="TEX">$1\leq p&lt; q=\infty $</EquationSource> </InlineEquation>, the average Nikolskii factor is of order <InlineEquation ID="IEq8"> <EquationSource Format="MATHML"><math> <msup> <mrow> <mo stretchy="false">(</mo> <mo>ln</mo> <mi>n</mi> <mo stretchy="false">)</mo> </mrow> <mrow> <mn>1</mn> <mo stretchy="false">/</mo> <mn>2</mn> </mrow> </msup> </math></EquationSource> <EquationSource Format="TEX">$(\ln n)^{1/2}$</EquationSource> </InlineEquation> as compared to the worst case bound of order <InlineEquation ID="IEq9"> <EquationSource Format="MATHML"><math> <msup> <mi>n</mi> <mrow> <mn>1</mn> <mo stretchy="false">/</mo> <mi>p</mi> </mrow> </msup> </math></EquationSource> <EquationSource Format="TEX">$n^{1/p}$</EquationSource> </InlineEquation>. We also give the generalization to random multivariate trigonometric polynomials.</p>

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Average Nikolskii factors for random trigonometric polynomials

  • Yun Ling,
  • Jiaxin Geng,
  • Jiansong Li,
  • Heping Wang

摘要

For 1 p , q $1\le p,q\le \infty $ , the Nikolskii factor for a trigonometric polynomial T a $T_{{\mathbf{a}}}$ is defined by N p , q ( T a ) = T a q T a p , T a ( x ) = a 1 + k = 1 n ( a 2 k 2 cos k x + a 2 k + 1 2 sin k x ) . \( N_{p,q}(T_{{\mathbf{a}}})= \frac{\|T_{{\mathbf{a}}}\|_{q}}{\|T_{{\mathbf{a}}}\|_{p}},\ \ T_{{ \mathbf{a}}}(x)=a_{1}+\sum \limits ^{n}_{k=1}(a_{2k}\sqrt{2}\cos kx+a_{2k+1} \sqrt{2}\sin kx). \) We study this average Nikolskii factor for random trigonometric polynomials with independent N ( 0 , σ 2 ) $N(0,\sigma ^{2})$ coefficients and obtain the exact orders. For 1 p < q < $1\leq p< q<\infty $ , the average Nikolskii factor is of order n 0 $n^{0}$ (i.e., constant), as compared to the worst case bound of order n 1 / p 1 / q $n^{1/p-1/q}$ , and for 1 p < q = $1\leq p< q=\infty $ , the average Nikolskii factor is of order ( ln n ) 1 / 2 $(\ln n)^{1/2}$ as compared to the worst case bound of order n 1 / p $n^{1/p}$ . We also give the generalization to random multivariate trigonometric polynomials.