<p>Let <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq1.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="55" /> </InlineMediaObject> <EquationSource Format="TEX">\(u_\alpha (x,t)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>u</mi> <mi>α</mi> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq2.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="69" /> </InlineMediaObject> <EquationSource Format="TEX">\(\alpha \in (0,2)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>α</mi> <mo>∈</mo> <mo stretchy="false">(</mo> <mn>0</mn> <mo>,</mo> <mn>2</mn> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> be the solution of the equation <Equation ID="Equ29"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_Equ29.gif" Format="GIF" Height="22" Rendition="HTML" Resolution="72" Type="Linedraw" Width="273" /> </MediaObject> <EquationSource Format="TEX">\(\Delta _{x,t} u_\alpha (x,t)+(1-\alpha )t^{-1}\partial _t u_\alpha (x,t)=0\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <msub> <mi mathvariant="normal">Δ</mi> <mrow> <mi>x</mi> <mo>,</mo> <mi>t</mi> </mrow> </msub> <msub> <mi>u</mi> <mi>α</mi> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> <mo>+</mo> <mrow> <mo stretchy="false">(</mo> <mn>1</mn> <mo>-</mo> <mi>α</mi> <mo stretchy="false">)</mo> </mrow> <msup> <mi>t</mi> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <msub> <mi>∂</mi> <mi>t</mi> </msub> <msub> <mi>u</mi> <mi>α</mi> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <mn>0</mn> </mrow> </math></EquationSource> </Equation>on <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq3.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="140" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {R}^{n+1}_+=\mathbb {R}^n\times (0,\infty )\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msubsup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mo>+</mo> <mrow> <mi>n</mi> <mo>+</mo> <mn>1</mn> </mrow> </msubsup> <mo>=</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo>×</mo> <mrow> <mo stretchy="false">(</mo> <mn>0</mn> <mo>,</mo> <mi>∞</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> subject to <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="110" /> </InlineMediaObject> <EquationSource Format="TEX">\(u_\alpha (x,0)=f(x)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>u</mi> <mi>α</mi> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mn>0</mn> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> on <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq5.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="20" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {R}^n\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> </math></EquationSource> </InlineEquation>. As the endpoint of the Poisson-Bessel potential <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq6.gif" Format="GIF" Height="12" Rendition="HTML" Resolution="72" Type="Linedraw" Width="20" /> </InlineMediaObject> <EquationSource Format="TEX">\(u_\alpha \)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi>u</mi> <mi>α</mi> </msub> </math></EquationSource> </InlineEquation>, the potential <InlineEquation ID="IEq7"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq7.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="53" /> </InlineMediaObject> <EquationSource Format="TEX">\(u_0(x,t)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>u</mi> <mn>0</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> solves the equation <Equation ID="Equ30"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_Equ30.gif" Format="GIF" Height="23" Rendition="HTML" Resolution="72" Type="Linedraw" Width="349" /> </MediaObject> <EquationSource Format="TEX">\( \Delta _{x,t} \big ((\ln t^{-1})u_0(x,t)\big )+t^{-1}\partial _t \big ((\ln t^{-1})u_0(x,t)\big )=0 \)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <msub> <mi mathvariant="normal">Δ</mi> <mrow> <mi>x</mi> <mo>,</mo> <mi>t</mi> </mrow> </msub> <mrow> <mo maxsize="1.2em" minsize="1.2em" stretchy="true">(</mo> </mrow> <mrow> <mo stretchy="false">(</mo> <mo>ln</mo> <msup> <mi>t</mi> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mo stretchy="false">)</mo> </mrow> <msub> <mi>u</mi> <mn>0</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> <mrow> <mo maxsize="1.2em" minsize="1.2em" stretchy="true">)</mo> </mrow> <mo>+</mo> <msup> <mi>t</mi> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <msub> <mi>∂</mi> <mi>t</mi> </msub> <mrow> <mo maxsize="1.2em" minsize="1.2em" stretchy="true">(</mo> </mrow> <mrow> <mo stretchy="false">(</mo> <mo>ln</mo> <msup> <mi>t</mi> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mo stretchy="false">)</mo> </mrow> <msub> <mi>u</mi> <mn>0</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> <mrow> <mo maxsize="1.2em" minsize="1.2em" stretchy="true">)</mo> </mrow> <mo>=</mo> <mn>0</mn> </mrow> </math></EquationSource> </Equation>on <InlineEquation ID="IEq8"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq8.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="34" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {R}^{n+1}_+\)</EquationSource> <EquationSource Format="MATHML"><math> <msubsup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mo>+</mo> <mrow> <mi>n</mi> <mo>+</mo> <mn>1</mn> </mrow> </msubsup> </math></EquationSource> </InlineEquation> subject to <InlineEquation ID="IEq9"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq9.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="109" /> </InlineMediaObject> <EquationSource Format="TEX">\(u_0(x,0)=f(x)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>u</mi> <mn>0</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mn>0</mn> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> on <InlineEquation ID="IEq10"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq10.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="20" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {R}^n\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> </math></EquationSource> </InlineEquation>. The main goal of this paper is to characterize a nonnegative measure <InlineEquation ID="IEq11"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq11.gif" Format="GIF" Height="12" Rendition="HTML" Resolution="72" Type="Linedraw" Width="15" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mu \)</EquationSource> <EquationSource Format="MATHML"><math> <mi>μ</mi> </math></EquationSource> </InlineEquation> on <InlineEquation ID="IEq12"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq12.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="34" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {R}^{n+1}_+\)</EquationSource> <EquationSource Format="MATHML"><math> <msubsup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mo>+</mo> <mrow> <mi>n</mi> <mo>+</mo> <mn>1</mn> </mrow> </msubsup> </math></EquationSource> </InlineEquation> such that <InlineEquation ID="IEq13"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq13.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="114" /> </InlineMediaObject> <EquationSource Format="TEX">\(f(x)\mapsto u_\alpha (x,t)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> <mo>↦</mo> <msub> <mi>u</mi> <mi>α</mi> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> induces a bounded embedding from the fractional <InlineEquation ID="IEq14"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq14.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="19" /> </InlineMediaObject> <EquationSource Format="TEX">\(L^1\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mi>L</mi> <mn>1</mn> </msup> </math></EquationSource> </InlineEquation>-Hardy-Sobolev space <InlineEquation ID="IEq15"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq15.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="64" /> </InlineMediaObject> <EquationSource Format="TEX">\(H^{\alpha ,1}(\mathbb {R}^n)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msup> <mi>H</mi> <mrow> <mi>α</mi> <mo>,</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq16"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq16.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="69" /> </InlineMediaObject> <EquationSource Format="TEX">\(\alpha \in (0,2)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>α</mi> <mo>∈</mo> <mo stretchy="false">(</mo> <mn>0</mn> <mo>,</mo> <mn>2</mn> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> into the weak Lebesgue space <InlineEquation ID="IEq17"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq17.gif" Format="GIF" Height="23" Rendition="HTML" Resolution="72" Type="Linedraw" Width="84" /> </InlineMediaObject> <EquationSource Format="TEX">\(WL^q_{\mu }(\mathbb {R}^{n+1}_+)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>W</mi> <msubsup> <mi>L</mi> <mi>μ</mi> <mi>q</mi> </msubsup> <mrow> <mo stretchy="false">(</mo> <msubsup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mo>+</mo> <mrow> <mi>n</mi> <mo>+</mo> <mn>1</mn> </mrow> </msubsup> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq18"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq18.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="75" /> </InlineMediaObject> <EquationSource Format="TEX">\(q\in [1,\infty )\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>q</mi> <mo>∈</mo> <mo stretchy="false">[</mo> <mn>1</mn> <mo>,</mo> <mi>∞</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq19"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq19.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="113" /> </InlineMediaObject> <EquationSource Format="TEX">\(f(x)\mapsto u_0(x,t)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>f</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> <mo>↦</mo> <msub> <mi>u</mi> <mn>0</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo>,</mo> <mi>t</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> induces a bounded embedding from the Hardy space <InlineEquation ID="IEq20"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq20.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="63" /> </InlineMediaObject> <EquationSource Format="TEX">\(H^{0,1}(\mathbb {R}^n)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msup> <mi>H</mi> <mrow> <mn>0</mn> <mo>,</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo stretchy="false">(</mo> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> into the Lebesgue space <InlineEquation ID="IEq21"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq21.gif" Format="GIF" Height="23" Rendition="HTML" Resolution="72" Type="Linedraw" Width="66" /> </InlineMediaObject> <EquationSource Format="TEX">\(L^q_{\mu }(\mathbb {R}^{n+1}_+)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msubsup> <mi>L</mi> <mi>μ</mi> <mi>q</mi> </msubsup> <mrow> <mo stretchy="false">(</mo> <msubsup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mo>+</mo> <mrow> <mi>n</mi> <mo>+</mo> <mn>1</mn> </mrow> </msubsup> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq22"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq22.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="75" /> </InlineMediaObject> <EquationSource Format="TEX">\(q\in [1,\infty )\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>q</mi> <mo>∈</mo> <mo stretchy="false">[</mo> <mn>1</mn> <mo>,</mo> <mi>∞</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>. Building upon the trace principles, we exploit <InlineEquation ID="IEq23"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq23.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="34" /> </InlineMediaObject> <EquationSource Format="TEX">\(H^{\alpha ,1}\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mi>H</mi> <mrow> <mi>α</mi> <mo>,</mo> <mn>1</mn> </mrow> </msup> </math></EquationSource> </InlineEquation> space for image characterization instead of the bounded variation space. Our proposed <InlineEquation ID="IEq24"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq24.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="71" /> </InlineMediaObject> <EquationSource Format="TEX">\((H^{\alpha ,1}, L^q)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <msup> <mi>H</mi> <mrow> <mi>α</mi> <mo>,</mo> <mn>1</mn> </mrow> </msup> <mo>,</mo> <msup> <mi>L</mi> <mi>q</mi> </msup> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq25"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="44007_2024_145_Article_IEq25.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="74" /> </InlineMediaObject> <EquationSource Format="TEX">\((H^{\alpha ,1}, \log )\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <msup> <mi>H</mi> <mrow> <mi>α</mi> <mo>,</mo> <mn>1</mn> </mrow> </msup> <mo>,</mo> <mo>log</mo> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> decomposition for image denoising demonstrate superior restorations, particularly in edges and texture preservation, when compared to the ROF model [<CitationRef CitationID="CR18">18</CitationRef>], as illustrated in the simulations.</p>

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A Trace Principle for Fractional Laplacian with an Application to Image Processing

  • J. Xiao,
  • C. Yue

摘要

Let \(u_\alpha (x,t)\) u α ( x , t ) , \(\alpha \in (0,2)\) α ( 0 , 2 ) be the solution of the equation \(\Delta _{x,t} u_\alpha (x,t)+(1-\alpha )t^{-1}\partial _t u_\alpha (x,t)=0\) Δ x , t u α ( x , t ) + ( 1 - α ) t - 1 t u α ( x , t ) = 0 on \(\mathbb {R}^{n+1}_+=\mathbb {R}^n\times (0,\infty )\) R + n + 1 = R n × ( 0 , ) subject to \(u_\alpha (x,0)=f(x)\) u α ( x , 0 ) = f ( x ) on \(\mathbb {R}^n\) R n . As the endpoint of the Poisson-Bessel potential \(u_\alpha \) u α , the potential \(u_0(x,t)\) u 0 ( x , t ) solves the equation \( \Delta _{x,t} \big ((\ln t^{-1})u_0(x,t)\big )+t^{-1}\partial _t \big ((\ln t^{-1})u_0(x,t)\big )=0 \) Δ x , t ( ( ln t - 1 ) u 0 ( x , t ) ) + t - 1 t ( ( ln t - 1 ) u 0 ( x , t ) ) = 0 on \(\mathbb {R}^{n+1}_+\) R + n + 1 subject to \(u_0(x,0)=f(x)\) u 0 ( x , 0 ) = f ( x ) on \(\mathbb {R}^n\) R n . The main goal of this paper is to characterize a nonnegative measure \(\mu \) μ on \(\mathbb {R}^{n+1}_+\) R + n + 1 such that \(f(x)\mapsto u_\alpha (x,t)\) f ( x ) u α ( x , t ) induces a bounded embedding from the fractional \(L^1\) L 1 -Hardy-Sobolev space \(H^{\alpha ,1}(\mathbb {R}^n)\) H α , 1 ( R n ) , \(\alpha \in (0,2)\) α ( 0 , 2 ) into the weak Lebesgue space \(WL^q_{\mu }(\mathbb {R}^{n+1}_+)\) W L μ q ( R + n + 1 ) , \(q\in [1,\infty )\) q [ 1 , ) and \(f(x)\mapsto u_0(x,t)\) f ( x ) u 0 ( x , t ) induces a bounded embedding from the Hardy space \(H^{0,1}(\mathbb {R}^n)\) H 0 , 1 ( R n ) into the Lebesgue space \(L^q_{\mu }(\mathbb {R}^{n+1}_+)\) L μ q ( R + n + 1 ) , \(q\in [1,\infty )\) q [ 1 , ) . Building upon the trace principles, we exploit \(H^{\alpha ,1}\) H α , 1 space for image characterization instead of the bounded variation space. Our proposed \((H^{\alpha ,1}, L^q)\) ( H α , 1 , L q ) and \((H^{\alpha ,1}, \log )\) ( H α , 1 , log ) decomposition for image denoising demonstrate superior restorations, particularly in edges and texture preservation, when compared to the ROF model [18], as illustrated in the simulations.