<p>In this article we investigate transcendental entire solutions of any order of the following partial differential difference equations: <Equation ID="Equ26"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="41478_2025_943_Article_Equ26.gif" Format="GIF" Height="46" Rendition="HTML" Resolution="72" Type="Linedraw" Width="333" /> </MediaObject> <EquationSource Format="TEX">\(\begin{aligned} f(z_1+c_1,z_2+c_2)^2+\left( \frac{\partial f(z_1,z_2)}{\partial z_1}\right) ^2=e^{2h(z_1,z_2)}\end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <mi>f</mi> <msup> <mrow> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>+</mo> <msub> <mi>c</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo>+</mo> <msub> <mi>c</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mn>2</mn> </msup> <mo>+</mo> <msup> <mfenced close=")" open="("> <mfrac> <mrow> <mi>∂</mi> <mi>f</mi> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mrow> <mi>∂</mi> <msub> <mi>z</mi> <mn>1</mn> </msub> </mrow> </mfrac> </mfenced> <mn>2</mn> </msup> <mo>=</mo> <msup> <mi>e</mi> <mrow> <mn>2</mn> <mi>h</mi> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> </msup> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>and <Equation ID="Equ27"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="41478_2025_943_Article_Equ27.gif" Format="GIF" Height="54" Rendition="HTML" Resolution="72" Type="Linedraw" Width="385" /> </MediaObject> <EquationSource Format="TEX">\(\begin{aligned}{\left\{ \begin{array}{ll} f(z_1+c_1,z_2+c_2)^2+g(z_1+c_1,z_2+c_2)^2=e^{2h(z_1,z_2)}, \\ \frac{\partial g(z_1,z_2)}{\partial z_1}^2+\frac{\partial f(z_1,z_2)}{\partial z_1}^2=1-e^{2h(z_1,z_2)}, \end{array}\right. }\end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mfenced open="{"> <mrow> <mtable> <mtr> <mtd columnalign="left"> <mrow> <mi>f</mi> <msup> <mrow> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>+</mo> <msub> <mi>c</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo>+</mo> <msub> <mi>c</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mn>2</mn> </msup> <mo>+</mo> <mi>g</mi> <msup> <mrow> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>+</mo> <msub> <mi>c</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo>+</mo> <msub> <mi>c</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mn>2</mn> </msup> <mo>=</mo> <msup> <mi>e</mi> <mrow> <mn>2</mn> <mi>h</mi> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> </msup> <mo>,</mo> </mrow> </mtd> </mtr> <mtr> <mtd columnalign="left"> <mrow> <mrow /> <msup> <mfrac> <mrow> <mi>∂</mi> <mi>g</mi> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mrow> <mi>∂</mi> <msub> <mi>z</mi> <mn>1</mn> </msub> </mrow> </mfrac> <mn>2</mn> </msup> <mo>+</mo> <msup> <mfrac> <mrow> <mi>∂</mi> <mi>f</mi> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mrow> <mi>∂</mi> <msub> <mi>z</mi> <mn>1</mn> </msub> </mrow> </mfrac> <mn>2</mn> </msup> <mo>=</mo> <mn>1</mn> <mo>-</mo> <msup> <mi>e</mi> <mrow> <mn>2</mn> <mi>h</mi> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> </msup> <mo>,</mo> </mrow> </mtd> </mtr> </mtable> </mrow> </mfenced> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>where <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="41478_2025_943_Article_IEq3.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="60" /> </InlineMediaObject> <EquationSource Format="TEX">\(h(z_1,z_2)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>h</mi> <mo stretchy="false">(</mo> <msub> <mi>z</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>z</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> is entire in <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="41478_2025_943_Article_IEq1.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="18" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {C}^2\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mrow> <mi mathvariant="double-struck">C</mi> </mrow> <mn>2</mn> </msup> </math></EquationSource> </InlineEquation> and obtain two new important and interesting results, which are the generalization of some of the previous results. Some examples have been exhibited which show that our results are precise.</p>

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On entire solutions of Fermat type partial differential difference equations in \(\mathbb {C}^2\)

  • Ashalata Roy,
  • Dilip Chandra Pramanik,
  • Goutam Haldar

摘要

In this article we investigate transcendental entire solutions of any order of the following partial differential difference equations: \(\begin{aligned} f(z_1+c_1,z_2+c_2)^2+\left( \frac{\partial f(z_1,z_2)}{\partial z_1}\right) ^2=e^{2h(z_1,z_2)}\end{aligned}\) f ( z 1 + c 1 , z 2 + c 2 ) 2 + f ( z 1 , z 2 ) z 1 2 = e 2 h ( z 1 , z 2 ) and \(\begin{aligned}{\left\{ \begin{array}{ll} f(z_1+c_1,z_2+c_2)^2+g(z_1+c_1,z_2+c_2)^2=e^{2h(z_1,z_2)}, \\ \frac{\partial g(z_1,z_2)}{\partial z_1}^2+\frac{\partial f(z_1,z_2)}{\partial z_1}^2=1-e^{2h(z_1,z_2)}, \end{array}\right. }\end{aligned}\) f ( z 1 + c 1 , z 2 + c 2 ) 2 + g ( z 1 + c 1 , z 2 + c 2 ) 2 = e 2 h ( z 1 , z 2 ) , g ( z 1 , z 2 ) z 1 2 + f ( z 1 , z 2 ) z 1 2 = 1 - e 2 h ( z 1 , z 2 ) , where \(h(z_1,z_2)\) h ( z 1 , z 2 ) is entire in \(\mathbb {C}^2\) C 2 and obtain two new important and interesting results, which are the generalization of some of the previous results. Some examples have been exhibited which show that our results are precise.