<p>Let <i>K</i> be a field of characteristic 0 and <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\(k \ge 2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>k</mi> <mo>≥</mo> <mn>2</mn> </mrow> </math></EquationSource> </InlineEquation> be an integer. We prove that every <i>K</i>-linear bijection <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(f : K[X] \rightarrow K[X]\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>f</mi> <mo>:</mo> <mi>K</mi> <mo stretchy="false">[</mo> <mi>X</mi> <mo stretchy="false">]</mo> <mo stretchy="false">→</mo> <mi>K</mi> <mo stretchy="false">[</mo> <mi>X</mi> <mo stretchy="false">]</mo> </mrow> </math></EquationSource> </InlineEquation> strongly preserving the set of <i>k</i>-free polynomials (or the set of polynomials with a <i>k</i>-fold root in <i>K</i>) is a constant multiple of a <i>K</i>-algebra automorphism of&#xa0;<i>K</i>[<i>X</i>], i.e., there are elements <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(a, c \in K^{\times }\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>a</mi> <mo>,</mo> <mi>c</mi> <mo>∈</mo> <msup> <mi>K</mi> <mo>×</mo> </msup> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\(b \in K\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>b</mi> <mo>∈</mo> <mi>K</mi> </mrow> </math></EquationSource> </InlineEquation> such that <InlineEquation ID="IEq5"> <EquationSource Format="TEX">\(f(P)(X) = c P(a X + b)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>f</mi> <mo stretchy="false">(</mo> <mi>P</mi> <mo stretchy="false">)</mo> <mo stretchy="false">(</mo> <mi>X</mi> <mo stretchy="false">)</mo> <mo>=</mo> <mi>c</mi> <mi>P</mi> <mo stretchy="false">(</mo> <mi>a</mi> <mi>X</mi> <mo>+</mo> <mi>b</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>. When <i>K</i> is a number field or <InlineEquation ID="IEq6"> <EquationSource Format="TEX">\(K=\mathbb {R}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>K</mi> <mo>=</mo> <mi mathvariant="double-struck">R</mi> </mrow> </math></EquationSource> </InlineEquation>, we prove that similar statements hold when <i>f</i> preserves the set of polynomials with a root in&#xa0;<i>K</i>.</p>

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Symmetries of various sets of polynomials

  • Béranger Seguin

摘要

Let K be a field of characteristic 0 and \(k \ge 2\) k 2 be an integer. We prove that every K-linear bijection \(f : K[X] \rightarrow K[X]\) f : K [ X ] K [ X ] strongly preserving the set of k-free polynomials (or the set of polynomials with a k-fold root in K) is a constant multiple of a K-algebra automorphism of K[X], i.e., there are elements \(a, c \in K^{\times }\) a , c K × , \(b \in K\) b K such that \(f(P)(X) = c P(a X + b)\) f ( P ) ( X ) = c P ( a X + b ) . When K is a number field or \(K=\mathbb {R}\) K = R , we prove that similar statements hold when f preserves the set of polynomials with a root in K.