<p>For some real quadratic numbers fields <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq1.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="11" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}\)</EquationSource> <EquationSource Format="MATHML"><math> <mi mathvariant="double-struck">k</mi> </math></EquationSource> </InlineEquation>, we aim, in this note, to give necessary and sufficient criteria for the 2-class group of <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq2.gif" Format="GIF" Height="24" Rendition="HTML" Resolution="72" Type="Linedraw" Width="26" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}_2^{(1)}\)</EquationSource> <EquationSource Format="MATHML"><math> <msubsup> <mi mathvariant="double-struck">k</mi> <mn>2</mn> <mrow> <mo stretchy="false">(</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> </msubsup> </math></EquationSource> </InlineEquation>, the first Hilbert 2-class field of <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq1.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="11" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}\)</EquationSource> <EquationSource Format="MATHML"><math> <mi mathvariant="double-struck">k</mi> </math></EquationSource> </InlineEquation>, to be cyclic. For this, we consider <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="114" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}=\mathbb {Q}(\sqrt{2pq_{1}q_{2}})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi mathvariant="double-struck">k</mi> <mo>=</mo> <mi mathvariant="double-struck">Q</mi> <mo stretchy="false">(</mo> <msqrt> <mrow> <mn>2</mn> <mi>p</mi> <msub> <mi>q</mi> <mn>1</mn> </msub> <msub> <mi>q</mi> <mn>2</mn> </msub> </mrow> </msqrt> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>, where <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq5.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="154" /> </InlineMediaObject> <EquationSource Format="TEX">\(p\equiv -q_{i}\equiv 1 \pmod 4\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>p</mi> <mo>≡</mo> <mo>-</mo> <msub> <mi>q</mi> <mi>i</mi> </msub> <mo>≡</mo> <mn>1</mn> <mspace width="4.44443pt" /> <mrow> <mo stretchy="false">(</mo> <mo>mod</mo> <mspace width="0.277778em" /> <mn>4</mn> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq6.gif" Format="GIF" Height="17" Rendition="HTML" Resolution="72" Type="Linedraw" Width="53" /> </InlineMediaObject> <EquationSource Format="TEX">\(i=1, 2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>i</mi> <mo>=</mo> <mn>1</mn> <mo>,</mo> <mn>2</mn> </mrow> </math></EquationSource> </InlineEquation>, are distinct prime integers, denote respectively by <InlineEquation ID="IEq7"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq7.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="29" /> </InlineMediaObject> <EquationSource Format="TEX">\(\textrm{C}_{\mathbb {k}, 2}\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mtext>C</mtext> <mrow> <mi mathvariant="double-struck">k</mi> <mo>,</mo> <mn>2</mn> </mrow> </msub> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq8"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq2.gif" Format="GIF" Height="24" Rendition="HTML" Resolution="72" Type="Linedraw" Width="26" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}_2^{(1)}\)</EquationSource> <EquationSource Format="MATHML"><math> <msubsup> <mi mathvariant="double-struck">k</mi> <mn>2</mn> <mrow> <mo stretchy="false">(</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> </msubsup> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq9"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq9.gif" Format="GIF" Height="24" Rendition="HTML" Resolution="72" Type="Linedraw" Width="26" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}_2^{(2)}\)</EquationSource> <EquationSource Format="MATHML"><math> <msubsup> <mi mathvariant="double-struck">k</mi> <mn>2</mn> <mrow> <mo stretchy="false">(</mo> <mn>2</mn> <mo stretchy="false">)</mo> </mrow> </msubsup> </math></EquationSource> </InlineEquation> the 2-class group, the first and the second Hilbert 2-class field of <InlineEquation ID="IEq10"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq1.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="11" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}\)</EquationSource> <EquationSource Format="MATHML"><math> <mi mathvariant="double-struck">k</mi> </math></EquationSource> </InlineEquation>. Put <InlineEquation ID="IEq11"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq11.gif" Format="GIF" Height="24" Rendition="HTML" Resolution="72" Type="Linedraw" Width="118" /> </InlineMediaObject> <EquationSource Format="TEX">\(G=Gal(\mathbb {k}_{2}^{(2)}/\mathbb {k})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>G</mi> <mo>=</mo> <mi>G</mi> <mi>a</mi> <mi>l</mi> <mo stretchy="false">(</mo> <msubsup> <mi mathvariant="double-struck">k</mi> <mrow> <mn>2</mn> </mrow> <mrow> <mo stretchy="false">(</mo> <mn>2</mn> <mo stretchy="false">)</mo> </mrow> </msubsup> <mo stretchy="false">/</mo> <mi mathvariant="double-struck">k</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>, the Galois group of <InlineEquation ID="IEq12"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq12.gif" Format="GIF" Height="24" Rendition="HTML" Resolution="72" Type="Linedraw" Width="43" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}_{2}^{(2)}/\mathbb {k}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msubsup> <mi mathvariant="double-struck">k</mi> <mrow> <mn>2</mn> </mrow> <mrow> <mo stretchy="false">(</mo> <mn>2</mn> <mo stretchy="false">)</mo> </mrow> </msubsup> <mo stretchy="false">/</mo> <mi mathvariant="double-struck">k</mi> </mrow> </math></EquationSource> </InlineEquation>, and <InlineEquation ID="IEq13"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq13.gif" Format="GIF" Height="24" Rendition="HTML" Resolution="72" Type="Linedraw" Width="137" /> </InlineMediaObject> <EquationSource Format="TEX">\(G'=Gal(\mathbb {k}_{2}^{(2)}/\mathbb {k}_{2}^{(1)})\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msup> <mi>G</mi> <mo>′</mo> </msup> <mo>=</mo> <mi>G</mi> <mi>a</mi> <mi>l</mi> <mrow> <mo stretchy="false">(</mo> <msubsup> <mi mathvariant="double-struck">k</mi> <mrow> <mn>2</mn> </mrow> <mrow> <mo stretchy="false">(</mo> <mn>2</mn> <mo stretchy="false">)</mo> </mrow> </msubsup> <mo stretchy="false">/</mo> <msubsup> <mi mathvariant="double-struck">k</mi> <mrow> <mn>2</mn> </mrow> <mrow> <mo stretchy="false">(</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> </msubsup> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> its derived subgroup. We are interested in studying the 4-rank of <InlineEquation ID="IEq14"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq7.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="29" /> </InlineMediaObject> <EquationSource Format="TEX">\(\textrm{C}_{\mathbb {k}, 2}\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mtext>C</mtext> <mrow> <mi mathvariant="double-struck">k</mi> <mo>,</mo> <mn>2</mn> </mrow> </msub> </math></EquationSource> </InlineEquation>, the metacyclicity of <i>G</i> and the cyclicity of <InlineEquation ID="IEq15"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq15.gif" Format="GIF" Height="15" Rendition="HTML" Resolution="72" Type="Linedraw" Width="20" /> </InlineMediaObject> <EquationSource Format="TEX">\(G'\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mi>G</mi> <mo>′</mo> </msup> </math></EquationSource> </InlineEquation> whenever the 4-rank of <InlineEquation ID="IEq16"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq16.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="92" /> </InlineMediaObject> <EquationSource Format="TEX">\(\textrm{C}_{\mathbb {k}, 2}\simeq G/G'\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mtext>C</mtext> <mrow> <mi mathvariant="double-struck">k</mi> <mo>,</mo> <mn>2</mn> </mrow> </msub> <mo>≃</mo> <mi>G</mi> <mo stretchy="false">/</mo> <msup> <mi>G</mi> <mo>′</mo> </msup> </mrow> </math></EquationSource> </InlineEquation> is 1. Moreover, in the metacyclic case, we investigate the capitulation of <InlineEquation ID="IEq17"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq7.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="29" /> </InlineMediaObject> <EquationSource Format="TEX">\(\textrm{C}_{\mathbb {k}, 2}\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mtext>C</mtext> <mrow> <mi mathvariant="double-struck">k</mi> <mo>,</mo> <mn>2</mn> </mrow> </msub> </math></EquationSource> </InlineEquation> in the unramified quadratic and biquadratic extensions of <InlineEquation ID="IEq18"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12215_2025_1236_Article_IEq1.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="11" /> </InlineMediaObject> <EquationSource Format="TEX">\(\mathbb {k}\)</EquationSource> <EquationSource Format="MATHML"><math> <mi mathvariant="double-struck">k</mi> </math></EquationSource> </InlineEquation>.</p>

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On the 2-class group of the first Hilbert class field of some real quadratic number fields

  • A. Ben Amar,
  • B. Aaboun,
  • A. Zekhnini

摘要

For some real quadratic numbers fields \(\mathbb {k}\) k , we aim, in this note, to give necessary and sufficient criteria for the 2-class group of \(\mathbb {k}_2^{(1)}\) k 2 ( 1 ) , the first Hilbert 2-class field of \(\mathbb {k}\) k , to be cyclic. For this, we consider \(\mathbb {k}=\mathbb {Q}(\sqrt{2pq_{1}q_{2}})\) k = Q ( 2 p q 1 q 2 ) , where \(p\equiv -q_{i}\equiv 1 \pmod 4\) p - q i 1 ( mod 4 ) , \(i=1, 2\) i = 1 , 2 , are distinct prime integers, denote respectively by \(\textrm{C}_{\mathbb {k}, 2}\) C k , 2 , \(\mathbb {k}_2^{(1)}\) k 2 ( 1 ) and \(\mathbb {k}_2^{(2)}\) k 2 ( 2 ) the 2-class group, the first and the second Hilbert 2-class field of \(\mathbb {k}\) k . Put \(G=Gal(\mathbb {k}_{2}^{(2)}/\mathbb {k})\) G = G a l ( k 2 ( 2 ) / k ) , the Galois group of \(\mathbb {k}_{2}^{(2)}/\mathbb {k}\) k 2 ( 2 ) / k , and \(G'=Gal(\mathbb {k}_{2}^{(2)}/\mathbb {k}_{2}^{(1)})\) G = G a l ( k 2 ( 2 ) / k 2 ( 1 ) ) its derived subgroup. We are interested in studying the 4-rank of \(\textrm{C}_{\mathbb {k}, 2}\) C k , 2 , the metacyclicity of G and the cyclicity of \(G'\) G whenever the 4-rank of \(\textrm{C}_{\mathbb {k}, 2}\simeq G/G'\) C k , 2 G / G is 1. Moreover, in the metacyclic case, we investigate the capitulation of \(\textrm{C}_{\mathbb {k}, 2}\) C k , 2 in the unramified quadratic and biquadratic extensions of \(\mathbb {k}\) k .