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Infinite order linear difference equation satisfied by a refinement of Goss zeta function

  • Su Hu,
  • Min-Soo Kim

摘要

At the international congress of mathematicians in 1900, Hilbert claimed that the Riemann zeta function \(\zeta (s)\) ζ ( s ) is not the solution of any algebraic ordinary differential equations on its region of analyticity. Let T be an infinite order linear differential operator introduced by Van Gorder in 2015. Recently, Prado and Klinger-Logan [9] showed that the Hurwitz zeta function \(\zeta (s,a)\) ζ ( s , a ) formally satisfies the following linear differential equation \(\begin{aligned} T\left[ \zeta (s,a) - \frac{1}{a^s}\right] = \frac{1}{(s-1)a^{s-1}}. \end{aligned}\) T ζ ( s , a ) - 1 a s = 1 ( s - 1 ) a s - 1 . Then in [6], by defining \(T_{p}^{a}\) T p a , a p-adic analogue of Van Gorder’s operator T,  we constructed the following convergent infinite order linear differential equation satisfied by the p-adic Hurwitz-type Euler zeta function \(\zeta _{p,E}(s,a)\) ζ p , E ( s , a ) \(\begin{aligned} T_{p}^{a}\left[ \zeta _{p,E}(s,a)-\langle a\rangle ^{1-s}\right] =\frac{1}{s-1}\left( \langle a-1 \rangle ^{1-s}-\langle a\rangle ^{1-s}\right) . \end{aligned}\) T p a ζ p , E ( s , a ) - a 1 - s = 1 s - 1 a - 1 1 - s - a 1 - s . In this paper, we consider this problem in the positive characteristic case. That is, by introducing \(\zeta _{\infty }(s_{0},s,a,n)\) ζ ( s 0 , s , a , n ) , a Hurwitz type refinement of Goss zeta function, and an infinite order linear difference operator L, we establish the following difference equation \(\begin{aligned} L\left[ \zeta _{\infty }\left( \frac{1}{T},s,a,0\right) \right] =\sum _{\gamma \in \mathbb {F}_{q}} \frac{1}{\langle a+\gamma \rangle ^{s}}. \end{aligned}\) L ζ 1 T , s , a , 0 = γ F q 1 a + γ s .