<p>This article contains a closed-form expression for the infinite series <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(\sum_{n=0}^{\infty}{1 \over (kn)!}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <munderover> <mo>∑</mo> <mrow> <mi>n</mi> <mo>=</mo> <mn>0</mn> </mrow> <mrow> <mi mathvariant="normal">∞</mi> </mrow> </munderover> <mrow> <mfrac> <mn>1</mn> <mrow> <mo stretchy="false">(</mo> <mi>k</mi> <mi>n</mi> <mo stretchy="false">)</mo> <mo>!</mo> </mrow> </mfrac> </mrow> </math></EquationSource> </InlineEquation>, where <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(k\in \mathbb{N}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mi>k</mi> <mo>∈</mo> <mrow> <mi mathvariant="double-struck">N</mi> </mrow> </math></EquationSource> </InlineEquation>. The solution is obtained using the series expression for exponential functions and roots of unity.</p>

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Closed-form Expression for the Series \(\sum_{n=0}^{\infty}{1 \over (kn)!}\)

  • Jewel Mahajan

摘要

This article contains a closed-form expression for the infinite series \(\sum_{n=0}^{\infty}{1 \over (kn)!}\) n = 0 1 ( k n ) ! , where \(k\in \mathbb{N}\) k N . The solution is obtained using the series expression for exponential functions and roots of unity.