For integers \(q_k\ge 2\) , let \(\{D_k=\{0,1,\cdots ,q_k-1\}\}_{k=1}^\infty \) be a sequence of digit sets and let \(\{b_k=q_kr_k\}_{k=1}^\infty \) be a sequences of integers. An et al. [4] have shown that the infinite convolution \(\begin{aligned} \mu _{\{b_k\},\{D_k\}}=\delta _{b_1^{-1}D_1}*\delta _{(b_1b_2)^{-1}D_2}*\delta _{(b_1b_2b_3)^{-1}D_3} *\cdots *\delta _{(b_1b_2\cdots b_k)^{-1}D_k}*\cdots \end{aligned}\) is a spectral measure. In this paper, we consider the spectral eigenvalue problem for \(\mu _{\{b_k\},\{D_k\}}\) , i.e., we seek conditions for real number t such that \(t\Lambda \) is also a spectrum of \(\mu _{\{b_k\},\{D_k\}}\) for some spectrum \(\Lambda \) . We deonstrate that t is a spectral eigenvalue of \(\mu _{\{b_k\},\{D_k\}}\) only if \(t=\frac{p}{q}\) for some integers p, q with \(\gcd (p,q)=1\) and \(\gcd (p,q_k)=\gcd (q,q_k)=1\) for all \(k\ge 1\) . Moreover, if \(\{\frac{b_k}{q_k}\}\) is unbounded, the necessary condition is also sufficient.