<p>Let <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="11139_2025_1191_Article_IEq1.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="19" /> </InlineMediaObject> <EquationSource Format="TEX">\([\theta ]\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">[</mo> <mi>θ</mi> <mo stretchy="false">]</mo> </mrow> </math></EquationSource> </InlineEquation> denote the integral part of the real number <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="11139_2025_1191_Article_IEq2.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="15" /> </InlineMediaObject> <EquationSource Format="TEX">\(\theta .\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>θ</mi> <mo>.</mo> </mrow> </math></EquationSource> </InlineEquation> In this paper, we prove that for <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="11139_2025_1191_Article_IEq3.gif" Format="GIF" Height="22" Rendition="HTML" Resolution="72" Type="Linedraw" Width="93" /> </InlineMediaObject> <EquationSource Format="TEX">\(1&lt;c&lt;\frac{11312}{10029}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mn>1</mn> <mo>&lt;</mo> <mi>c</mi> <mo>&lt;</mo> <mfrac> <mn>11312</mn> <mn>10029</mn> </mfrac> </mrow> </math></EquationSource> </InlineEquation> and a sufficiently large integer <i>N</i>, the Diophantine equation <Equation ID="Equ37"> <MediaObject> <ImageObject Color="BlackWhite" FileRef="11139_2025_1191_Article_Equ37.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="150" /> </MediaObject> <EquationSource Format="TEX">\(\begin{aligned} [p_{1}^{c}]+[p_{2}^{c}]+[p_{3}^{c}]=N \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <mrow> <mo stretchy="false">[</mo> <msubsup> <mi>p</mi> <mrow> <mn>1</mn> </mrow> <mi>c</mi> </msubsup> <mo stretchy="false">]</mo> </mrow> <mo>+</mo> <mrow> <mo stretchy="false">[</mo> <msubsup> <mi>p</mi> <mrow> <mn>2</mn> </mrow> <mi>c</mi> </msubsup> <mo stretchy="false">]</mo> </mrow> <mo>+</mo> <mrow> <mo stretchy="false">[</mo> <msubsup> <mi>p</mi> <mrow> <mn>3</mn> </mrow> <mi>c</mi> </msubsup> <mo stretchy="false">]</mo> </mrow> <mo>=</mo> <mi>N</mi> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>is solvable in prime variables <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="11139_2025_1191_Article_IEq4.gif" Format="GIF" Height="12" Rendition="HTML" Resolution="72" Type="Linedraw" Width="62" /> </InlineMediaObject> <EquationSource Format="TEX">\(p_1,p_2,p_3\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>p</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>p</mi> <mn>2</mn> </msub> <mo>,</mo> <msub> <mi>p</mi> <mn>3</mn> </msub> </mrow> </math></EquationSource> </InlineEquation> such that <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="11139_2025_1191_Article_IEq5.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="119" /> </InlineMediaObject> <EquationSource Format="TEX">\(p_1=x^2+y^2+1\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>p</mi> <mn>1</mn> </msub> <mo>=</mo> <msup> <mi>x</mi> <mn>2</mn> </msup> <mo>+</mo> <msup> <mi>y</mi> <mn>2</mn> </msup> <mo>+</mo> <mn>1</mn> </mrow> </math></EquationSource> </InlineEquation> with integers <i>x</i> and <i>y</i>. Moreover, we establish the corresponding asymptotic formula.</p>

错误:搜索内容不能为空,请输入英文关键词
错误:关键词超出字数限制,请精简
高级检索

On a Diophantine equation involving one Linnik prime

  • Yuhui Liu

摘要

Let \([\theta ]\) [ θ ] denote the integral part of the real number \(\theta .\) θ . In this paper, we prove that for \(1<c<\frac{11312}{10029}\) 1 < c < 11312 10029 and a sufficiently large integer N, the Diophantine equation \(\begin{aligned} [p_{1}^{c}]+[p_{2}^{c}]+[p_{3}^{c}]=N \end{aligned}\) [ p 1 c ] + [ p 2 c ] + [ p 3 c ] = N is solvable in prime variables \(p_1,p_2,p_3\) p 1 , p 2 , p 3 such that \(p_1=x^2+y^2+1\) p 1 = x 2 + y 2 + 1 with integers x and y. Moreover, we establish the corresponding asymptotic formula.