<p>In this paper, we investigate the Diophantine equation <Equation ID="Equ7"> <EquationSource Format="TEX">\(\begin{aligned} (2^k - 1)(3^k - 1) = x^n \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <mrow> <mo stretchy="false">(</mo> <msup> <mn>2</mn> <mi>k</mi> </msup> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> <mrow> <mo stretchy="false">(</mo> <msup> <mn>3</mn> <mi>k</mi> </msup> <mo>-</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <msup> <mi>x</mi> <mi>n</mi> </msup> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>and prove that it has no solution in positive integers <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(k, x, n &gt; 2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>k</mi> <mo>,</mo> <mi>x</mi> <mo>,</mo> <mi>n</mi> <mo>&gt;</mo> <mn>2</mn> </mrow> </math></EquationSource> </InlineEquation>.</p>

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The diophantine equation \((2^{k}-1)(3^{k}-1)=x^{n}\)

  • Bo He,
  • Chang Liu

摘要

In this paper, we investigate the Diophantine equation \(\begin{aligned} (2^k - 1)(3^k - 1) = x^n \end{aligned}\) ( 2 k - 1 ) ( 3 k - 1 ) = x n and prove that it has no solution in positive integers \(k, x, n > 2\) k , x , n > 2 .