<p>Let <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\(\mathrm E_6\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi mathvariant="normal">E</mi> <mn>6</mn> </msub> </math></EquationSource> </InlineEquation> denote the simply-connected compact exceptional Lie group of rank 6. The Lie group <InlineEquation ID="IEq5"> <EquationSource Format="TEX">\(\textrm{Spin}(10)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mtext>Spin</mtext> <mo stretchy="false">(</mo> <mn>10</mn> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> naturally embeds in <InlineEquation ID="IEq6"> <EquationSource Format="TEX">\(\mathrm E_6\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi mathvariant="normal">E</mi> <mn>6</mn> </msub> </math></EquationSource> </InlineEquation>, corresponding to the inclusion of the Dynkin diagrams. We determine the <i>K</i>-ring of the coset space <InlineEquation ID="IEq7"> <EquationSource Format="TEX">\(\mathrm E_6/\textrm{Spin}(10)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi mathvariant="normal">E</mi> <mn>6</mn> </msub> <mo stretchy="false">/</mo> <mtext>Spin</mtext> <mrow> <mo stretchy="false">(</mo> <mn>10</mn> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation>. We identify the class of the tangent bundle of <InlineEquation ID="IEq8"> <EquationSource Format="TEX">\(\mathrm E_6/\textrm{Spin}(10)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi mathvariant="normal">E</mi> <mn>6</mn> </msub> <mo stretchy="false">/</mo> <mtext>Spin</mtext> <mrow> <mo stretchy="false">(</mo> <mn>10</mn> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> in <InlineEquation ID="IEq9"> <EquationSource Format="TEX">\(KO(\mathrm E_6/\textrm{Spin}(10))\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>K</mi> <mi>O</mi> <mo stretchy="false">(</mo> <msub> <mi mathvariant="normal">E</mi> <mn>6</mn> </msub> <mo stretchy="false">/</mo> <mtext>Spin</mtext> <mrow> <mo stretchy="false">(</mo> <mn>10</mn> <mo stretchy="false">)</mo> </mrow> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>. As an application we show that <InlineEquation ID="IEq10"> <EquationSource Format="TEX">\(\mathrm E_6/\textrm{Spin}(10)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi mathvariant="normal">E</mi> <mn>6</mn> </msub> <mo stretchy="false">/</mo> <mtext>Spin</mtext> <mrow> <mo stretchy="false">(</mo> <mn>10</mn> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> can be immersed in the Euclidean space <InlineEquation ID="IEq11"> <EquationSource Format="TEX">\(\mathbb {R}^{53}\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mn>53</mn> </msup> </math></EquationSource> </InlineEquation> but not in <InlineEquation ID="IEq12"> <EquationSource Format="TEX">\(\mathbb {R}^{40}.\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msup> <mrow> <mi mathvariant="double-struck">R</mi> </mrow> <mn>40</mn> </msup> <mo>.</mo> </mrow> </math></EquationSource> </InlineEquation></p>

错误:搜索内容不能为空,请输入英文关键词
错误:关键词超出字数限制,请精简
高级检索

The K-ring of \(\mathrm E_6/\textrm{Spin}(10)\)

  • Sudeep Podder,
  • Parameswaran Sankaran

摘要

Let \(\mathrm E_6\) E 6 denote the simply-connected compact exceptional Lie group of rank 6. The Lie group \(\textrm{Spin}(10)\) Spin ( 10 ) naturally embeds in \(\mathrm E_6\) E 6 , corresponding to the inclusion of the Dynkin diagrams. We determine the K-ring of the coset space \(\mathrm E_6/\textrm{Spin}(10)\) E 6 / Spin ( 10 ) . We identify the class of the tangent bundle of \(\mathrm E_6/\textrm{Spin}(10)\) E 6 / Spin ( 10 ) in \(KO(\mathrm E_6/\textrm{Spin}(10))\) K O ( E 6 / Spin ( 10 ) ) . As an application we show that \(\mathrm E_6/\textrm{Spin}(10)\) E 6 / Spin ( 10 ) can be immersed in the Euclidean space \(\mathbb {R}^{53}\) R 53 but not in \(\mathbb {R}^{40}.\) R 40 .