<p>The main question of this paper is the following: how much cancellation can the partial sums restricted to the <i>k</i>-free integers up to <i>x</i> of a <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="574_2025_453_Article_IEq1.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="24" /> </InlineMediaObject> <EquationSource Format="TEX">\(\pm 1\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo>±</mo> <mn>1</mn> </mrow> </math></EquationSource> </InlineEquation> multiplicative function <i>f</i> be in terms of <i>x</i>? Building upon the recent paper by Liu (Acta Math Sin (Engl Ser) 39(12):2316–2328, 2023), we prove that under the Riemann Hypothesis for quadratic Dirichlet <i>L</i>-functions, we can get <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="574_2025_453_Article_IEq2.gif" Format="GIF" Height="18" Rendition="HTML" Resolution="72" Type="Linedraw" Width="54" /> </InlineMediaObject> <EquationSource Format="TEX">\(x^{1/(k+1)}\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mi>x</mi> <mrow> <mn>1</mn> <mo stretchy="false">/</mo> <mo stretchy="false">(</mo> <mi>k</mi> <mo>+</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> </msup> </math></EquationSource> </InlineEquation> cancellation when <i>f</i> is a modified quadratic Dirichlet character, i.e., <i>f</i> is completely multiplicative and for some quadratic Dirichlet character <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="574_2025_453_Article_IEq3.gif" Format="GIF" Height="12" Rendition="HTML" Resolution="72" Type="Linedraw" Width="15" /> </InlineMediaObject> <EquationSource Format="TEX">\(\chi \)</EquationSource> <EquationSource Format="MATHML"><math> <mi>χ</mi> </math></EquationSource> </InlineEquation>, <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="574_2025_453_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="87" /> </InlineMediaObject> <EquationSource Format="TEX">\(f(p)=\chi (p)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>f</mi> <mo stretchy="false">(</mo> <mi>p</mi> <mo stretchy="false">)</mo> <mo>=</mo> <mi>χ</mi> <mo stretchy="false">(</mo> <mi>p</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> for all but a finite subset of prime numbers. This improves the conditional results by Aymone et al. (Ramanujan J 59(3):713–728, 2022).</p>

错误:搜索内容不能为空,请输入英文关键词
错误:关键词超出字数限制,请精简
高级检索

Modified Dirichlet Character Sums over the k-free Integers

  • Caio Bueno

摘要

The main question of this paper is the following: how much cancellation can the partial sums restricted to the k-free integers up to x of a \(\pm 1\) ± 1 multiplicative function f be in terms of x? Building upon the recent paper by Liu (Acta Math Sin (Engl Ser) 39(12):2316–2328, 2023), we prove that under the Riemann Hypothesis for quadratic Dirichlet L-functions, we can get \(x^{1/(k+1)}\) x 1 / ( k + 1 ) cancellation when f is a modified quadratic Dirichlet character, i.e., f is completely multiplicative and for some quadratic Dirichlet character \(\chi \) χ , \(f(p)=\chi (p)\) f ( p ) = χ ( p ) for all but a finite subset of prime numbers. This improves the conditional results by Aymone et al. (Ramanujan J 59(3):713–728, 2022).