<p>In this article we propose a probabilistic framework in order to study the fair division of a divisible good, e.g. a cake, between <i>n</i> players. Our framework corresponds to the “Full independence model" used in the study of fair division of indivisible goods. We show that, if we consider a uniform distribution in this framework, then there exists an envy-free division algorithm satisfying the following probability estimate: <Equation ID="Equ1"> <EquationSource Format="TEX">\(\begin{aligned} \mathbb {P}\left( C\left( \mu _1, \ldots ,\mu _n\right) \ge n^{7+b}\right) = \mathcal {O}\left( n^{-\frac{b-1}{3}+1+o(1)}\right) , \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <mi mathvariant="double-struck">P</mi> <mfenced close=")" open="("> <mi>C</mi> <mfenced close=")" open="("> <msub> <mi>μ</mi> <mn>1</mn> </msub> <mo>,</mo> <mo>…</mo> <mo>,</mo> <msub> <mi>μ</mi> <mi>n</mi> </msub> </mfenced> <mo>≥</mo> <msup> <mi>n</mi> <mrow> <mn>7</mn> <mo>+</mo> <mi>b</mi> </mrow> </msup> </mfenced> <mo>=</mo> <mi mathvariant="script">O</mi> <mfenced close=")" open="("> <msup> <mi>n</mi> <mrow> <mo>-</mo> <mfrac> <mrow> <mi>b</mi> <mo>-</mo> <mn>1</mn> </mrow> <mn>3</mn> </mfrac> <mo>+</mo> <mn>1</mn> <mo>+</mo> <mi>o</mi> <mrow> <mo stretchy="false">(</mo> <mn>1</mn> <mo stretchy="false">)</mo> </mrow> </mrow> </msup> </mfenced> <mo>,</mo> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>where <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\(\mu _1,\ldots , \mu _n\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>μ</mi> <mn>1</mn> </msub> <mo>,</mo> <mo>…</mo> <mo>,</mo> <msub> <mi>μ</mi> <mi>n</mi> </msub> </mrow> </math></EquationSource> </InlineEquation> correspond to the preferences of the <i>n</i> players, <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(C(\mu _1, \ldots ,\mu _n)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>C</mi> <mo stretchy="false">(</mo> <msub> <mi>μ</mi> <mn>1</mn> </msub> <mo>,</mo> <mo>…</mo> <mo>,</mo> <msub> <mi>μ</mi> <mi>n</mi> </msub> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> is the number of queries used by the algorithm and <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(b&gt;4\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>b</mi> <mo>&gt;</mo> <mn>4</mn> </mrow> </math></EquationSource> </InlineEquation>. In particular, this gives <Equation ID="Equ2"> <EquationSource Format="TEX">\(\begin{aligned} \lim _{n \rightarrow + \infty }\mathbb {P}\left( C(\mu _1, \ldots ,\mu _n) \ge n^{12}\right) = 0. \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <munder> <mo movablelimits="true">lim</mo> <mrow> <mi>n</mi> <mo stretchy="false">→</mo> <mo>+</mo> <mi>∞</mi> </mrow> </munder> <mi mathvariant="double-struck">P</mi> <mfenced close=")" open="("> <mi>C</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>μ</mi> <mn>1</mn> </msub> <mo>,</mo> <mo>…</mo> <mo>,</mo> <msub> <mi>μ</mi> <mi>n</mi> </msub> <mo stretchy="false">)</mo> </mrow> <mo>≥</mo> <msup> <mi>n</mi> <mn>12</mn> </msup> </mfenced> <mo>=</mo> <mn>0</mn> <mo>.</mo> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>It must be noticed that nowadays few things are known about the complexity of envy-free division algorithms. Indeed, Procaccia has given a lower bound in <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\(\Omega (n^2)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi mathvariant="normal">Ω</mi> <mo stretchy="false">(</mo> <msup> <mi>n</mi> <mn>2</mn> </msup> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> and Aziz and Mackenzie have given an upper bound in <InlineEquation ID="IEq5"> <EquationSource Format="TEX">\(n^{n^{n^{n^{n^{n}}}}}\)</EquationSource> <EquationSource Format="MATHML"><math> <msup> <mi>n</mi> <msup> <mi>n</mi> <msup> <mi>n</mi> <msup> <mi>n</mi> <msup> <mi>n</mi> <mi>n</mi> </msup> </msup> </msup> </msup> </msup> </math></EquationSource> </InlineEquation>. As our estimate means that we have <InlineEquation ID="IEq6"> <EquationSource Format="TEX">\(C(\mu _1, \ldots , \mu _n)&lt;n^{12}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>C</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>μ</mi> <mn>1</mn> </msub> <mo>,</mo> <mo>…</mo> <mo>,</mo> <msub> <mi>μ</mi> <mi>n</mi> </msub> <mo stretchy="false">)</mo> </mrow> <mo>&lt;</mo> <msup> <mi>n</mi> <mn>12</mn> </msup> </mrow> </math></EquationSource> </InlineEquation> with a high probability, this gives a new insight on the complexity of envy-free cake cutting algorithms. Our result follows from a study of Webb’s algorithm and a theorem of Tao and Vu about the smallest singular value of a random matrix.</p>

错误:搜索内容不能为空,请输入英文关键词
错误:关键词超出字数限制,请精简
高级检索

Envy-free cake cutting: a polynomial number of queries with high probability

  • Guillaume Chèze

摘要

In this article we propose a probabilistic framework in order to study the fair division of a divisible good, e.g. a cake, between n players. Our framework corresponds to the “Full independence model" used in the study of fair division of indivisible goods. We show that, if we consider a uniform distribution in this framework, then there exists an envy-free division algorithm satisfying the following probability estimate: \(\begin{aligned} \mathbb {P}\left( C\left( \mu _1, \ldots ,\mu _n\right) \ge n^{7+b}\right) = \mathcal {O}\left( n^{-\frac{b-1}{3}+1+o(1)}\right) , \end{aligned}\) P C μ 1 , , μ n n 7 + b = O n - b - 1 3 + 1 + o ( 1 ) , where \(\mu _1,\ldots , \mu _n\) μ 1 , , μ n correspond to the preferences of the n players, \(C(\mu _1, \ldots ,\mu _n)\) C ( μ 1 , , μ n ) is the number of queries used by the algorithm and \(b>4\) b > 4 . In particular, this gives \(\begin{aligned} \lim _{n \rightarrow + \infty }\mathbb {P}\left( C(\mu _1, \ldots ,\mu _n) \ge n^{12}\right) = 0. \end{aligned}\) lim n + P C ( μ 1 , , μ n ) n 12 = 0 . It must be noticed that nowadays few things are known about the complexity of envy-free division algorithms. Indeed, Procaccia has given a lower bound in \(\Omega (n^2)\) Ω ( n 2 ) and Aziz and Mackenzie have given an upper bound in \(n^{n^{n^{n^{n^{n}}}}}\) n n n n n n . As our estimate means that we have \(C(\mu _1, \ldots , \mu _n)<n^{12}\) C ( μ 1 , , μ n ) < n 12 with a high probability, this gives a new insight on the complexity of envy-free cake cutting algorithms. Our result follows from a study of Webb’s algorithm and a theorem of Tao and Vu about the smallest singular value of a random matrix.