<p>The Cartesian product of graphs <i>G</i> and <i>H</i> is the graph <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq1.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="45" /> </InlineMediaObject> <EquationSource Format="TEX">\(G \Box H\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>G</mi> <mo>□</mo> <mi>H</mi> </mrow> </math></EquationSource> </InlineEquation> whose vertex set is <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq2.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="103" /> </InlineMediaObject> <EquationSource Format="TEX">\(V (G)\times V (H)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>V</mi> <mo stretchy="false">(</mo> <mi>G</mi> <mo stretchy="false">)</mo> <mo>×</mo> <mi>V</mi> <mo stretchy="false">(</mo> <mi>H</mi> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> and whose edge set is the set of all pairs <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq3.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="102" /> </InlineMediaObject> <EquationSource Format="TEX">\((u_1,v_1)(u_2,v_2)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mrow> <mo stretchy="false">(</mo> <msub> <mi>u</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>v</mi> <mn>1</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mrow> <mo stretchy="false">(</mo> <msub> <mi>u</mi> <mn>2</mn> </msub> <mo>,</mo> <msub> <mi>v</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> such that either <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq4.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="94" /> </InlineMediaObject> <EquationSource Format="TEX">\(u_1u_2 \in E(G)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>u</mi> <mn>1</mn> </msub> <msub> <mi>u</mi> <mn>2</mn> </msub> <mo>∈</mo> <mi>E</mi> <mrow> <mo stretchy="false">(</mo> <mi>G</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq5.gif" Format="GIF" Height="12" Rendition="HTML" Resolution="72" Type="Linedraw" Width="52" /> </InlineMediaObject> <EquationSource Format="TEX">\(v_1 = v_2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>v</mi> <mn>1</mn> </msub> <mo>=</mo> <msub> <mi>v</mi> <mn>2</mn> </msub> </mrow> </math></EquationSource> </InlineEquation>, or <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq6.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="93" /> </InlineMediaObject> <EquationSource Format="TEX">\(v_1v_2 \in E(H)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>v</mi> <mn>1</mn> </msub> <msub> <mi>v</mi> <mn>2</mn> </msub> <mo>∈</mo> <mi>E</mi> <mrow> <mo stretchy="false">(</mo> <mi>H</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq7"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq7.gif" Format="GIF" Height="12" Rendition="HTML" Resolution="72" Type="Linedraw" Width="55" /> </InlineMediaObject> <EquationSource Format="TEX">\(u_1 = u_2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>u</mi> <mn>1</mn> </msub> <mo>=</mo> <msub> <mi>u</mi> <mn>2</mn> </msub> </mrow> </math></EquationSource> </InlineEquation>. The multiple extended complete split-like graph <InlineEquation ID="IEq8"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq8.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="72" /> </InlineMediaObject> <EquationSource Format="TEX">\(MECS_{b,s}^{a}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>M</mi> <mi>E</mi> <mi>C</mi> <msubsup> <mi>S</mi> <mrow> <mi>b</mi> <mo>,</mo> <mi>s</mi> </mrow> <mi>a</mi> </msubsup> </mrow> </math></EquationSource> </InlineEquation> is the join graph of an empty graph <InlineEquation ID="IEq9"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq9.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="25" /> </InlineMediaObject> <EquationSource Format="TEX">\({\overline{K}}_a\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mover> <mi>K</mi> <mo>¯</mo> </mover> <mi>a</mi> </msub> </math></EquationSource> </InlineEquation> and <i>s</i> copies of <InlineEquation ID="IEq10"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq10.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="55" /> </InlineMediaObject> <EquationSource Format="TEX">\(K_b\Box K_2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>K</mi> <mi>b</mi> </msub> <mo>□</mo> <msub> <mi>K</mi> <mn>2</mn> </msub> </mrow> </math></EquationSource> </InlineEquation>, where <InlineEquation ID="IEq11"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq10.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="55" /> </InlineMediaObject> <EquationSource Format="TEX">\(K_b\Box K_2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>K</mi> <mi>b</mi> </msub> <mo>□</mo> <msub> <mi>K</mi> <mn>2</mn> </msub> </mrow> </math></EquationSource> </InlineEquation> is the Cartesian product of complete graphs <InlineEquation ID="IEq12"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq12.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="23" /> </InlineMediaObject> <EquationSource Format="TEX">\(K_b\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi>K</mi> <mi>b</mi> </msub> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq13"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="34_2025_3124_Article_IEq13.gif" Format="GIF" Height="16" Rendition="HTML" Resolution="72" Type="Linedraw" Width="22" /> </InlineMediaObject> <EquationSource Format="TEX">\(K_2\)</EquationSource> <EquationSource Format="MATHML"><math> <msub> <mi>K</mi> <mn>2</mn> </msub> </math></EquationSource> </InlineEquation>. In this paper, we derive the resistance distance and the number of spanning trees of multiple extended complete split-like graph.</p>

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Resistance Distance and Spanning Trees of Multiple Extended Complete Split-Like Graph

  • Chenlin Yang,
  • Tao Tian

摘要

The Cartesian product of graphs G and H is the graph \(G \Box H\) G H whose vertex set is \(V (G)\times V (H)\) V ( G ) × V ( H ) and whose edge set is the set of all pairs \((u_1,v_1)(u_2,v_2)\) ( u 1 , v 1 ) ( u 2 , v 2 ) such that either \(u_1u_2 \in E(G)\) u 1 u 2 E ( G ) and \(v_1 = v_2\) v 1 = v 2 , or \(v_1v_2 \in E(H)\) v 1 v 2 E ( H ) and \(u_1 = u_2\) u 1 = u 2 . The multiple extended complete split-like graph \(MECS_{b,s}^{a}\) M E C S b , s a is the join graph of an empty graph \({\overline{K}}_a\) K ¯ a and s copies of \(K_b\Box K_2\) K b K 2 , where \(K_b\Box K_2\) K b K 2 is the Cartesian product of complete graphs \(K_b\) K b and \(K_2\) K 2 . In this paper, we derive the resistance distance and the number of spanning trees of multiple extended complete split-like graph.