<p>In his 1934 paper, G. Birkhoff poses the problem of classifying pairs (<i>G</i>,&#xa0;<i>U</i>) where <i>G</i> is an abelian group and <InlineEquation ID="IEq3"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2150_Article_IEq3.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="54" /> </InlineMediaObject> <EquationSource Format="TEX">\(U\subset G\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>U</mi> <mo>⊂</mo> <mi>G</mi> </mrow> </math></EquationSource> </InlineEquation> a subgroup, up to automorphisms of <i>G</i>. In general, Birkhoff’s problem is not considered feasible. In this note, we fix a prime number <i>p</i> and assume that <i>G</i> is a direct sum of cyclic <i>p</i>-groups and <InlineEquation ID="IEq4"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2150_Article_IEq3.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="54" /> </InlineMediaObject> <EquationSource Format="TEX">\(U\subset G\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>U</mi> <mo>⊂</mo> <mi>G</mi> </mrow> </math></EquationSource> </InlineEquation> is a&#xa0;subgroup. Under the assumption that the factor group <i>G</i>/<i>U</i> is an elementary abelian <i>p</i>-group, we show that the pair (<i>G</i>,&#xa0;<i>U</i>) always has a direct sum decomposition into pairs of type <InlineEquation ID="IEq5"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2150_Article_IEq5.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="116" /> </InlineMediaObject> <EquationSource Format="TEX">\(({\mathbb {Z}}/(p^n),{\mathbb {Z}}/(p^n))\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi mathvariant="double-struck">Z</mi> <mo stretchy="false">/</mo> <mrow> <mo stretchy="false">(</mo> <msup> <mi>p</mi> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <mi mathvariant="double-struck">Z</mi> <mo stretchy="false">/</mo> <mrow> <mo stretchy="false">(</mo> <msup> <mi>p</mi> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> or <InlineEquation ID="IEq6"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2150_Article_IEq6.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="89" /> </InlineMediaObject> <EquationSource Format="TEX">\((\mathbb {Z}/(p^n), (p))\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi mathvariant="double-struck">Z</mi> <mo stretchy="false">/</mo> <mrow> <mo stretchy="false">(</mo> <msup> <mi>p</mi> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <mrow> <mo stretchy="false">(</mo> <mi>p</mi> <mo stretchy="false">)</mo> </mrow> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation>. Surprisingly, in the dual situation, we need an additional condition. If we assume that <i>U</i> itself is an elementary subgroup of <i>G</i>, then we show that the pair (<i>G</i>,&#xa0;<i>U</i>) has a direct sum decomposition into pairs of type <InlineEquation ID="IEq7"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2150_Article_IEq7.gif" Format="GIF" Height="19" Rendition="HTML" Resolution="72" Type="Linedraw" Width="77" /> </InlineMediaObject> <EquationSource Format="TEX">\(({\mathbb {Z}}/(p^n),0)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi mathvariant="double-struck">Z</mi> <mo stretchy="false">/</mo> <mrow> <mo stretchy="false">(</mo> <msup> <mi>p</mi> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <mn>0</mn> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> or <InlineEquation ID="IEq8"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2150_Article_IEq8.gif" Format="GIF" Height="20" Rendition="HTML" Resolution="72" Type="Linedraw" Width="112" /> </InlineMediaObject> <EquationSource Format="TEX">\((\mathbb {Z}/(p^n), (p^{n-1}))\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mo stretchy="false">(</mo> <mi mathvariant="double-struck">Z</mi> <mo stretchy="false">/</mo> <mrow> <mo stretchy="false">(</mo> <msup> <mi>p</mi> <mi>n</mi> </msup> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <mrow> <mo stretchy="false">(</mo> <msup> <mi>p</mi> <mrow> <mi>n</mi> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mo stretchy="false">)</mo> </mrow> <mo stretchy="false">)</mo> </mrow> </math></EquationSource> </InlineEquation> if and only if <i>G</i>/<i>U</i> is a&#xa0;direct sum of cyclic <i>p</i>-groups. We generalize the above results to modules over commutative discrete valuation rings.</p>

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Abelian \(p\)-groups with a fixed elementary subgroup or with a fixed elementary quotient

  • Justyna Kosakowska,
  • Markus Schmidmeier,
  • Martin Schreiner

摘要

In his 1934 paper, G. Birkhoff poses the problem of classifying pairs (GU) where G is an abelian group and \(U\subset G\) U G a subgroup, up to automorphisms of G. In general, Birkhoff’s problem is not considered feasible. In this note, we fix a prime number p and assume that G is a direct sum of cyclic p-groups and \(U\subset G\) U G is a subgroup. Under the assumption that the factor group G/U is an elementary abelian p-group, we show that the pair (GU) always has a direct sum decomposition into pairs of type \(({\mathbb {Z}}/(p^n),{\mathbb {Z}}/(p^n))\) ( Z / ( p n ) , Z / ( p n ) ) or \((\mathbb {Z}/(p^n), (p))\) ( Z / ( p n ) , ( p ) ) . Surprisingly, in the dual situation, we need an additional condition. If we assume that U itself is an elementary subgroup of G, then we show that the pair (GU) has a direct sum decomposition into pairs of type \(({\mathbb {Z}}/(p^n),0)\) ( Z / ( p n ) , 0 ) or \((\mathbb {Z}/(p^n), (p^{n-1}))\) ( Z / ( p n ) , ( p n - 1 ) ) if and only if G/U is a direct sum of cyclic p-groups. We generalize the above results to modules over commutative discrete valuation rings.