<p>Let <i>K</i> be a global field, that is, a number field or a global function field. It is known that the answer to the question in the title over <i>K</i> is “Yes” when <i>K</i> has no real embeddings. We show that otherwise the answer is “No”. Namely, we show that when <i>K</i> is a number field admitting a real embedding, it is impossible to define a group structure on the first Galois cohomology sets <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="13_2025_2118_Article_IEq1.gif" Format="GIF" Height="21" Rendition="HTML" Resolution="72" Type="Linedraw" Width="67" /> </InlineMediaObject> <EquationSource Format="TEX">\(\textrm{H}^1\hspace{-0.8pt}(K,G)\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msup> <mtext>H</mtext> <mn>1</mn> </msup> <mspace width="-0.8pt" /> <mrow> <mo stretchy="false">(</mo> <mi>K</mi> <mo>,</mo> <mi>G</mi> <mo stretchy="false">)</mo> </mrow> </mrow> </math></EquationSource> </InlineEquation> for all reductive <i>K</i>-groups <i>G</i> in a functorial way.</p>

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Is there a group structure on the Galois cohomology of a reductive group over a global field?

  • Mikhail Borovoi

摘要

Let K be a global field, that is, a number field or a global function field. It is known that the answer to the question in the title over K is “Yes” when K has no real embeddings. We show that otherwise the answer is “No”. Namely, we show that when K is a number field admitting a real embedding, it is impossible to define a group structure on the first Galois cohomology sets \(\textrm{H}^1\hspace{-0.8pt}(K,G)\) H 1 ( K , G ) for all reductive K-groups G in a functorial way.