<p>A poset <InlineEquation ID="IEq1"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12_2025_892_Article_IEq1.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="13" /> </InlineMediaObject> <EquationSource Format="TEX">\({\mathbb {X}}\)</EquationSource> <EquationSource Format="MATHML"><math> <mi mathvariant="double-struck">X</mi> </math></EquationSource> </InlineEquation> is said to be zigzag image-finite, if the least updownset (i.e., both an upset and a downset) containing <i>x</i> is finite, for all <InlineEquation ID="IEq2"> <InlineMediaObject> <ImageObject Color="BlackWhite" FileRef="12_2025_892_Article_IEq2.gif" Format="GIF" Height="14" Rendition="HTML" Resolution="72" Type="Linedraw" Width="52" /> </InlineMediaObject> <EquationSource Format="TEX">\(x\in X.\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>x</mi> <mo>∈</mo> <mi>X</mi> <mo>.</mo> </mrow> </math></EquationSource> </InlineEquation> We show that a bi-Heyting algebra is profinite if and only if it is isomorphic to the lattice of upsets of a zigzag image-finite poset. Zigzag image-finite posets have the property of being disjoint unions of finite connected posets. Because of this, we equivalently show that a bi-Heyting algebra is profinite if and only if it is isomorphic to a direct product of simple finite bi-Heyting algebras.</p>

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Profinite bi-Heyting algebras

  • Lydia Tasiou

摘要

A poset \({\mathbb {X}}\) X is said to be zigzag image-finite, if the least updownset (i.e., both an upset and a downset) containing x is finite, for all \(x\in X.\) x X . We show that a bi-Heyting algebra is profinite if and only if it is isomorphic to the lattice of upsets of a zigzag image-finite poset. Zigzag image-finite posets have the property of being disjoint unions of finite connected posets. Because of this, we equivalently show that a bi-Heyting algebra is profinite if and only if it is isomorphic to a direct product of simple finite bi-Heyting algebras.