<p>Our main objective is to solve the hexagonal functional equation <Equation ID="Equ40"> <EquationSource Format="TEX">\(\begin{aligned} F(x_1&amp;\rho (y_1), x_2 \sigma (y_2)) - F(x_1 \rho (y_1), x_2) - F(x_1, x_2 \sigma (y_2))\\&amp;= F(x_1 y_1, x_2 y_2) - F(x_1 y_1, x_2) - F(x_1, x_2 y_2) \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <mi>F</mi> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mn>1</mn> </msub> </mrow> </mtd> <mtd columnalign="left"> <mrow> <mi>ρ</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>y</mi> <mn>1</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <msub> <mi>x</mi> <mn>2</mn> </msub> <mi>σ</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>y</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mrow> <mo stretchy="false">)</mo> <mo>-</mo> <mi>F</mi> </mrow> <mrow> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mn>1</mn> </msub> <mi>ρ</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>y</mi> <mn>1</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <msub> <mi>x</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mo>-</mo> <mi>F</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>x</mi> <mn>2</mn> </msub> <mi>σ</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>y</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mo stretchy="false">)</mo> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd columnalign="right"> <mrow /> </mtd> <mtd columnalign="left"> <mrow> <mo>=</mo> <mi>F</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mn>1</mn> </msub> <msub> <mi>y</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>x</mi> <mn>2</mn> </msub> <msub> <mi>y</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mo>-</mo> <mi>F</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mn>1</mn> </msub> <msub> <mi>y</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>x</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> <mo>-</mo> <mi>F</mi> <mrow> <mo stretchy="false">(</mo> <msub> <mi>x</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>x</mi> <mn>2</mn> </msub> <msub> <mi>y</mi> <mn>2</mn> </msub> <mo stretchy="false">)</mo> </mrow> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>for an unknown <InlineEquation ID="IEq1"> <EquationSource Format="TEX">\(F: S_1\times S_2 \rightarrow H\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>F</mi> <mo>:</mo> <msub> <mi>S</mi> <mn>1</mn> </msub> <mo>×</mo> <msub> <mi>S</mi> <mn>2</mn> </msub> <mo stretchy="false">→</mo> <mi>H</mi> </mrow> </math></EquationSource> </InlineEquation>, where <InlineEquation ID="IEq2"> <EquationSource Format="TEX">\(S_1,S_2\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>S</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>S</mi> <mn>2</mn> </msub> </mrow> </math></EquationSource> </InlineEquation> are monoids with respective involutions <InlineEquation ID="IEq3"> <EquationSource Format="TEX">\(\rho \)</EquationSource> <EquationSource Format="MATHML"><math> <mi>ρ</mi> </math></EquationSource> </InlineEquation> and <InlineEquation ID="IEq4"> <EquationSource Format="TEX">\(\sigma \)</EquationSource> <EquationSource Format="MATHML"><math> <mi>σ</mi> </math></EquationSource> </InlineEquation>, and <i>H</i> is an Abelian group. Our method uses results about the solutions <InlineEquation ID="IEq5"> <EquationSource Format="TEX">\(f_1,f_2,f_3:S \rightarrow H\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>f</mi> <mn>1</mn> </msub> <mo>,</mo> <msub> <mi>f</mi> <mn>2</mn> </msub> <mo>,</mo> <msub> <mi>f</mi> <mn>3</mn> </msub> <mo>:</mo> <mi>S</mi> <mo stretchy="false">→</mo> <mi>H</mi> </mrow> </math></EquationSource> </InlineEquation> of <Equation ID="Equ41"> <EquationSource Format="TEX">\(\begin{aligned} f_1(xy)+ f_2(x\sigma (y)) = f_3(x), \quad x,y \in S, \end{aligned}\)</EquationSource> <EquationSource Format="MATHML"><math display="block"> <mrow> <mtable> <mtr> <mtd columnalign="right"> <mrow> <msub> <mi>f</mi> <mn>1</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mi>y</mi> <mo stretchy="false">)</mo> </mrow> <mo>+</mo> <msub> <mi>f</mi> <mn>2</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mi>σ</mi> <mrow> <mo stretchy="false">(</mo> <mi>y</mi> <mo stretchy="false">)</mo> </mrow> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <msub> <mi>f</mi> <mn>3</mn> </msub> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> <mo>,</mo> <mspace width="1em" /> <mi>x</mi> <mo>,</mo> <mi>y</mi> <mo>∈</mo> <mi>S</mi> <mo>,</mo> </mrow> </mtd> </mtr> </mtable> </mrow> </math></EquationSource> </Equation>which is a Pexiderized version of the extended Jensen equation on semigroups. We are motivated by some earlier results about similar functional equations on groups. In those results the equation is considered for <InlineEquation ID="IEq6"> <EquationSource Format="TEX">\(S_1 = S_2 = G\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <msub> <mi>S</mi> <mn>1</mn> </msub> <mo>=</mo> <msub> <mi>S</mi> <mn>2</mn> </msub> <mo>=</mo> <mi>G</mi> </mrow> </math></EquationSource> </InlineEquation>, a group, and with <InlineEquation ID="IEq7"> <EquationSource Format="TEX">\(H = {\mathbb {C}}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>H</mi> <mo>=</mo> <mi mathvariant="double-struck">C</mi> </mrow> </math></EquationSource> </InlineEquation>. Chung <i>et al.</i> (J. Korean Math. Soc. <b>38</b>, 37-47 (2001)) solved the main equation under the assumptions that <i>G</i> is a 2-divisible group and <InlineEquation ID="IEq8"> <EquationSource Format="TEX">\(\rho (x) = \sigma (x) = x^{-1}\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>ρ</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <mi>σ</mi> <mrow> <mo stretchy="false">(</mo> <mi>x</mi> <mo stretchy="false">)</mo> </mrow> <mo>=</mo> <msup> <mi>x</mi> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> </mrow> </math></EquationSource> </InlineEquation> for all <InlineEquation ID="IEq9"> <EquationSource Format="TEX">\(x \in G\)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>x</mi> <mo>∈</mo> <mi>G</mi> </mrow> </math></EquationSource> </InlineEquation>. Later Hunt <i>et al.</i> (Aequat. Math. <b>90</b>, 87-96 (2016)) studied the special case <InlineEquation ID="IEq10"> <EquationSource Format="TEX">\(\rho = \sigma \)</EquationSource> <EquationSource Format="MATHML"><math> <mrow> <mi>ρ</mi> <mo>=</mo> <mi>σ</mi> </mrow> </math></EquationSource> </InlineEquation> of our equation on a general group, and Lin <i>et al.</i> (Aequat. Math. <b>97</b>, 639-648 (2023)) studied our equation on a general group. The authors of the latter two articles claim that they solved the respective equations without assuming that the group <i>S</i> is 2-divisible, but some solutions are missing. We correct the latter two results and extend all three results to the case that <i>S</i> is a monoid.</p>

错误:搜索内容不能为空,请输入英文关键词
错误:关键词超出字数限制,请精简
高级检索

A hexagonal functional equation

  • Bruce Ebanks

摘要

Our main objective is to solve the hexagonal functional equation \(\begin{aligned} F(x_1&\rho (y_1), x_2 \sigma (y_2)) - F(x_1 \rho (y_1), x_2) - F(x_1, x_2 \sigma (y_2))\\&= F(x_1 y_1, x_2 y_2) - F(x_1 y_1, x_2) - F(x_1, x_2 y_2) \end{aligned}\) F ( x 1 ρ ( y 1 ) , x 2 σ ( y 2 ) ) - F ( x 1 ρ ( y 1 ) , x 2 ) - F ( x 1 , x 2 σ ( y 2 ) ) = F ( x 1 y 1 , x 2 y 2 ) - F ( x 1 y 1 , x 2 ) - F ( x 1 , x 2 y 2 ) for an unknown \(F: S_1\times S_2 \rightarrow H\) F : S 1 × S 2 H , where \(S_1,S_2\) S 1 , S 2 are monoids with respective involutions \(\rho \) ρ and \(\sigma \) σ , and H is an Abelian group. Our method uses results about the solutions \(f_1,f_2,f_3:S \rightarrow H\) f 1 , f 2 , f 3 : S H of \(\begin{aligned} f_1(xy)+ f_2(x\sigma (y)) = f_3(x), \quad x,y \in S, \end{aligned}\) f 1 ( x y ) + f 2 ( x σ ( y ) ) = f 3 ( x ) , x , y S , which is a Pexiderized version of the extended Jensen equation on semigroups. We are motivated by some earlier results about similar functional equations on groups. In those results the equation is considered for \(S_1 = S_2 = G\) S 1 = S 2 = G , a group, and with \(H = {\mathbb {C}}\) H = C . Chung et al. (J. Korean Math. Soc. 38, 37-47 (2001)) solved the main equation under the assumptions that G is a 2-divisible group and \(\rho (x) = \sigma (x) = x^{-1}\) ρ ( x ) = σ ( x ) = x - 1 for all \(x \in G\) x G . Later Hunt et al. (Aequat. Math. 90, 87-96 (2016)) studied the special case \(\rho = \sigma \) ρ = σ of our equation on a general group, and Lin et al. (Aequat. Math. 97, 639-648 (2023)) studied our equation on a general group. The authors of the latter two articles claim that they solved the respective equations without assuming that the group S is 2-divisible, but some solutions are missing. We correct the latter two results and extend all three results to the case that S is a monoid.